Re: Discussion Problems of the Day (15-06-11)

Posted by barkha on Jun 18, 2011; 6:13am
URL: http://discussion-forum.276.s1.nabble.com/Discussion-Problems-of-the-Day-15-06-11-tp6477247p6490074.html

Ashima,

Start by finding out total no ways in which 52 cards can be distributed among 4 people, 13 cards each. This works out out to be  52C13*39C13*26C13*13C13. true that each ace can go to any of the four players but there are other cards which are to to be distributed as well so that each receives 13 cards each. And no of favorable cases whereby all four aces go to one person is given by 4 times 4C4*48C9*39C13*26C13*13C13.(As there are four aces and 48 non ace cards and all aces can be received by any of four players)