Re: maths

Posted by anon_econ on Jan 29, 2012; 1:15pm
URL: http://discussion-forum.276.s1.nabble.com/maths-tp7233645p7234306.html

The equality holds for x=y as well. So u must have 2xf(x)=2x[f(x)]^2. Solve this to get f(x)[f(x)-1]=0, when x is not =0.
This means that when x is not equal to 0, f(x) is either 0 or 1. Since f is a continuous function, f(0) also has to have the same value as f(x) when x is not =0.
Thus u get 2 continuous functions: f(x)=0 and f(x)=1.

I don't know how to do that probability question.