Re: dse 2011

Posted by duck on Mar 09, 2012; 4:22am
URL: http://discussion-forum.276.s1.nabble.com/dse-2011-tp7342784p7357076.html

Hi Ritu.. :)

Suppose, we have 3 non zero linearly dependent vectors such that:
c1*v1 + c2 *v2 + c3*V3 =0

=> v1 = -(c2/c1)*v2 -(c3/c1)*v3

Now, if you take only one scalar(let it be c1) to be non zero and other two (c2 and c3) be zero
then, v1 = 0 but v1 is a non zero vector which is a contradiction.
Hence, minimum number is 2 and not 1.