Re: isi 2009

Posted by sunny2009 on Apr 03, 2012; 6:19am
URL: http://discussion-forum.276.s1.nabble.com/isi-2009-tp7430781p7431924.html

question number 14
lim (n tends to infinity) (1^2+2^2+....+n^2)/n^3
                       implies {n(n+1)(2n+1)}/6n^3
                      implies 2n^2+3n+1/6n^2
                      implies 1/3+1/2n+1/6n^2
                      implies 1/3   (when n tends to infinity)
 so answer should be 1/3 in my opinion.