Re: JNU-11

Posted by ritu on May 08, 2012; 6:49am
URL: http://discussion-forum.276.s1.nabble.com/JNU-11-tp7537760p7538026.html

or u can think of any equation like x^2-3x+2....solve it u get the zeroes as 1 and 2.....
now solve for (x-2)^2-3(x-2)+2 nd solve it u get zeroes as 3 nd 4...so in general u just need to add two to all the zeroes to get the  values for second question..just always be careful about the sign..:)