Re: ISI 2004 ME - I Answer Key

Posted by ritu on May 09, 2012; 1:47pm
URL: http://discussion-forum.276.s1.nabble.com/ISI-2004-ME-I-Answer-Key-tp7515784p7542924.html

hi aj..:) well that was fab...but fortunately i have got a shorter method....
we have a formula of perpendicular distance from a given point to a given line....
D= { ax+by+c/under root a^2+ b^2}    this whole expression is within mod
now can take the point on curve as (x1,y1)
since this given point lies on y=x^2....we have y1=x1^2
put these values of (x1,y1) for (x,y) and u get D in terms of x1 only....now just minimise d nd u get x1=1 which implies y1=1

hope u find it crispier..:PPP