Re: ISI 2004 ME - I Answer Key

Posted by archita on May 11, 2012; 4:28am
URL: http://discussion-forum.276.s1.nabble.com/ISI-2004-ME-I-Answer-Key-tp7515784p7549156.html

plz explain question 28 again.....
i didnt get expresiion e^{ 1/x^2[sinx-x]/x} ,,,sholudnt it be e^[1/x^2*ln (sinx/x)]  ?