Re: PDF - June 13
Posted by Chinni18 on Jun 13, 2012; 4:11pm
URL: http://discussion-forum.276.s1.nabble.com/PDF-June-13-tp7577697p7577706.html
I only got it because I had done this question a month or so ago and really broke my head over it
The radius of the circle will be either x,y,1-x or 1-y
=>D= 2min{x,y,1-x or 1-y}
So P((D<= d) = 1 - P(D > d) which comes out to be 1-(1-d)^2 ie 2d- d^2
Try drawing the circle in the square as specified in the question, then you'll get it.
For PDF I differentiated cdf wrt d
URL: http://discussion-forum.276.s1.nabble.com/PDF-June-13-tp7577697p7577706.html
I only got it because I had done this question a month or so ago and really broke my head over it
The radius of the circle will be either x,y,1-x or 1-y
=>D= 2min{x,y,1-x or 1-y}
So P((D<= d) = 1 - P(D > d) which comes out to be 1-(1-d)^2 ie 2d- d^2
Try drawing the circle in the square as specified in the question, then you'll get it.
For PDF I differentiated cdf wrt d
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