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Re: ISI INTERVIEW PREP

Posted by Brajesh on Jul 08, 2012; 7:55pm
URL: http://discussion-forum.276.s1.nabble.com/ISI-INTERVIEW-PREP-tp7578819p7579242.html

if    4x+5y=n
=>  4(x+y)+y= n
now taking x-1 no. of x and y+1 no. of y
then
4[(x-1)+(y+1)]+y+1= n'
=> 4[x+y]+y+1= n'= n+1