Re: ISI 2012 ME - I Answer Key

Posted by Preet on Jul 09, 2012; 6:17am
URL: http://discussion-forum.276.s1.nabble.com/ISI-2012-ME-I-Answer-Key-tp7515795p7579247.html

Well  lets see..
For each n€N; define An = {(n + 1)k : k€N}

Say i chose an n= 1 then
A1= {2k} for k€N => A1= {2,4,6,8,10,12,..,18....}
A2= {3k} for k€N => A2= {3,6,9,12,15,18}

Now,  A1∩A2= (6,12,18....)
i.e. A1∩A2 = A5= {(n+1)k for k€N and n=5}

surbhi sharma wrote

shouldnt the answer of q3 A6..???