Re: probab
Posted by
Akshay Jain on
Apr 26, 2013; 5:20pm
URL: http://discussion-forum.276.s1.nabble.com/probab-tp7580185p7580189.html
total no. of possible arrangements = (n-1)! (circular permutations) = 7!
total no. of ways in which 5 boys can be arranged at alternate positions = 5!
there are total 5 positions left among boys in which 3 girls have to be seated so that no two girls are together= 5P3
requared probability= 5!*5P3/7!=2/7
Akshay Jain
Masters in Economics
Delhi School of Economics
2013-15