Re: functions problem

Posted by MI on May 01, 2013; 2:13pm
URL: http://discussion-forum.276.s1.nabble.com/functions-problem-tp7580283p7580285.html



f(x+y)+f(x-y)=2f(x)f(y)

putting x=y=0

2f(0) = 2 square(f(0))

Given f(0) != 0

f(0)=1

putting x=0 in topmost given equation

f(y) +f(-y) = 2f(y)

=> f is an even function