Re: jnuQ

Posted by Sinistral on May 08, 2013; 5:51am
URL: http://discussion-forum.276.s1.nabble.com/jnuQ-tp7580475p7580478.html

10) d

dA/dt = uA
solving gives: A=exp(ut+c), c is a constant

similarly, dB/dt=(u+1)B
B= exp[(u+1)t+k]

at t=0, A=B ==> c=k

t=1: A=exp(u+c)
       B=exp(u+1+c)=exp(u+c)*exp(1)=Ae, ie A times e