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Re: DSE 2011 Queries

Posted by duck on May 13, 2013; 4:34pm
URL: http://discussion-forum.276.s1.nabble.com/DSE-2011-Queries-tp7580646p7580653.html

27) C1 ∩ C2 = (C1' ∪ C2')'
Note: C1' denotes complement of C1.
Now, C1' is a tribe and C2' is also a tribe. And union is two tribes is a tribe therefore, (C1' ∪ C2') is a tribe. Hence, complement of (C1' ∪ C2') = (C1' ∪ C2')' will be a club.Hence, option(a)

28) C1 ∪ C2 = (C1' ∩ C2')'
Now, C1' and C2' are tribes. So, their intersection will also be a tribe. And therefore, the complement of
(C1' ∩ C2') = (C1 ∩ C2)' will be a club. Hence, option(c)

29) Society and Empty set are both Club and Tribe.Hence, option(b)

30)Given a tribe T1 and a club C2: (T1 ∩ C2') is a club since C2' is  a tribe and the intersection of two tribes is a tribe. Hence, option(b)
:)