Re: Discussion Problem_(14)

Posted by Sumit on May 25, 2013; 10:01am
URL: http://discussion-forum.276.s1.nabble.com/Discussion-Problem-14-tp7581214p7581218.html

If P1<P2 then (M/p1,0)
& If P1>P2 then (0,M/p2)
& If P1=P2 then either (M/p1,0) or (0,M/p2).