Re: DSE 2006

Posted by Sinistral on May 28, 2013; 4:39pm
URL: http://discussion-forum.276.s1.nabble.com/DSE-2006-tp7581393p7581399.html

to find the vertical asymptotes set denominator =0 ==> x=0 ==> y axis is the vertical asymptote.

oblique asymptote:
(x^2+2x-1)/x
= x+2 - (1/x)
when x --> infinity the above function tends to x+2 ==> y=x+2 is the other asymptote.

so option c