Re: Discussion Problem_(28)

Posted by Mauli on Jun 02, 2013; 5:02am
URL: http://discussion-forum.276.s1.nabble.com/Discussion-Problem-28-tp7581662p7581669.html

q1)
since the pr(x) winning and  pr(y) winning are independent  of each other.
we have pr(x) = 6/14 pr(x') = 8/14 where..x=winning
                                                         x'= not winning
similarly for y =
pr(y)=14/30 and pr(y')= 16/30
required pr = pr(x)*pr(y') +pr(x')*pr(y)+pr(x)*pr(y)=73/105

q2)
integral over 0 to 1
3x^2 *x*x*(1-x) dx = 1/10
please cnfrm wthr my methods and answers are correct.