Re: SPEED question

Posted by Bankelal on Dec 01, 2013; 10:03am
URL: http://discussion-forum.276.s1.nabble.com/SPEED-question-tp7584279p7584286.html

Hi XIPP,

My name is Aditya! (Well i prefer Adi :) )

For our earlier eqn:

5/(x-y)+ 5/(x+y)=5/y.

Take 5/x common from both sides, and we have

1/(1 - y/x) + 1/(1 + y/x) = 1/(y/x)

Take y/x = z.(for simplification purpose only)

=> 1/(1-z) + 1/(1+z) = 1/z   

=> 2/(1-z^2)=1/z

or z^2 -2z -1 = 0

On solving z, 

z = (2 +-8^(1/2))/2 = (1+-2^1/2)/1 =x/y

And that's last missing piece of our puzzle!

On Sun, Dec 1, 2013 at 10:57 AM, XIPP [via Discussion forum] <[hidden email]> wrote:

Thank you sir. How did you derive x/y ? I am stuck here:
see this  and I can't get  x/y = (1 +- 2^1/2)/1. Where am I wrong?

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