Re: Maths doubt

Posted by Amit Goyal on Apr 16, 2014; 1:54am
URL: http://discussion-forum.276.s1.nabble.com/Maths-doubt-tp7586601p7586991.html

Q 3
Pr (X^2>1, Y^3<(-1))
= Pr(X^2> 1)Pr(Y^3 < -1)   [Since X and Y are independent]
= [Pr(X < -1) + Pr(X > 1)] Pr(Y < -1)
= [p + p]p  [Since X and Y are random variables with standard normal distributions and Pr(X < -1) = p]
= 2p^2