Re: Permutations problem

Posted by vandita24x7 on Apr 28, 2014; 3:49pm
URL: http://discussion-forum.276.s1.nabble.com/Permutations-problem-tp7587982p7588002.html

There is a definite formula for such a question when division into groups is asked. That is
(m+n)!/m!*n!
Where m and n refer to the amount of each group. So here as the total is 27 and u need to divide into groups of 3. So (m+n) is 27 and m!=n!=3! . So in a way acc to the formula u get 27!/(3!*3!*3!*3!*3!*3!*3!*3!*3!)
Which is same as 27!/(3!)^9  ok.

vandita

On 28 Apr 2014 21:02, "ViV [via Discussion forum]" <[hidden email]> wrote:

here we are dividing by 9! because all 9 groups are having same no. of persons.

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