Re: Quadratic polynomial problem

Posted by Dreyfus on May 01, 2014; 11:26am
URL: http://discussion-forum.276.s1.nabble.com/Quadratic-polynomial-problem-tp7588142p7588148.html

Tsuki...draw a graph of polynomial nd at x=1 if p(x) =t den at x=2 p(x)=-t now this means that b/w these two numbers p(x) changes its sign nd since px is polynomial hence continuous which implies that px when changed its sign from 1 to 2 den it must have become 0 somewhere b/w 1 nd 2