Re: IS1-2008 ME1 answer key link

Posted by Dreyfus on May 06, 2014; 3:47pm
URL: http://discussion-forum.276.s1.nabble.com/IS1-2008-ME1-answer-key-link-tp7588727p7588749.html

Kangkan...we r given that x is greater than 0
So when 0<x<1 then x^(-2n) would tend to infinity as n tends to infinity
When x=1 then x^(-2n) would become indeterminate as n tnds to infinity
And when x>1 then x^(-2n) would tend to 0 as n tends to infinity
Therefore no limit exist