Re: DSE 2013 Paper Discussion

Posted by Granpa Simpson on May 20, 2014; 9:10am
URL: http://discussion-forum.276.s1.nabble.com/DSE-2013-Paper-Discussion-tp7584703p7590250.html

β=0, implies y=α,
in this case y=mean of y=α.
So clearly (Y-mean of Y)=TSS=0.
Now use R^2=ESS/TSS, so clearly since TSS=0, R^2 is undefined.
Note: Here ESS=[Y(hat)-Y(bar)]^2.