Re: DSE 2012

Posted by kangkan on May 20, 2014; 7:03pm
URL: http://discussion-forum.276.s1.nabble.com/DSE-2012-tp7590190p7590309.html

integrate it by parts ..let X^ndx=dv and sinx=u..


we get I= X^n+1/n+1 - int (from 0 to 1) cosx *X^n+1 /(n+1)dx...now X^(n+1)cosX is always positive in the int 0 to 1.   hence 1/n+1 - something...hence it will be always less than 1/n+1