Re: Doubts DSE 2004

Posted by kangkan on Jun 07, 2014; 7:15pm
URL: http://discussion-forum.276.s1.nabble.com/Doubts-DSE-2004-tp7591874p7591876.html

30...it will be 2p^2...prob(X^2>1)= prob(  |x|<1)=2p  prob (y^3>1)=prob(y>1)=p (by symmetry of standard noraml distri).

there fore ans=2p*p=2p^2