Re: Differentiability query !!

Posted by mrittik on Jun 13, 2014; 8:22am
URL: http://discussion-forum.276.s1.nabble.com/Differentiability-query-tp7592592p7592593.html

f(x)=(x-1)-(x-2)-(x-3)=-x+4, x>1
     =-3x+ 6 x<1

now you can do this easily with 2 & 3 also...so now this is no where differentiable