Re: Functions

Posted by onionknight on Nov 04, 2014; 3:32pm
URL: http://discussion-forum.276.s1.nabble.com/Functions-tp7595615p7595616.html

The range of the function sin(x) is [-1,1] . Therefore, the domain of the function sin^-1(y) is -[-1,1]. In the function f(x)= sin^-1(log3(x/3)), you can read log3(x/3) as y. Hence -1<log3(x/3)<1 which implies that 3^(-1) < x/3 < 3^(1) which gives us 1/3 < x <3 and finally 1<x<9 (Both included in the domain) .

Hope this helps.