Re: ISI PEA 2015 discussion

Posted by Ankita on May 11, 2015; 3:50am
URL: http://discussion-forum.276.s1.nabble.com/ISI-PEA-2015-discussion-tp7596744p7596784.html

This should be the answer nC3/[(nC2)C3].   I think it was option (b)

where nC3 is the number of ways of choosing 3 points on the circle from 'n' points.