Re: ISI PEA 2015 discussion

Posted by Ankita on May 11, 2015; 7:41am
URL: http://discussion-forum.276.s1.nabble.com/ISI-PEA-2015-discussion-tp7596744p7596830.html

Wait.. zero must be correct but how does f(x,y)=x-y satisfy the following condition:
f(x,y)+f(y,z)+f(z,x)=1
x-y+y-z+z-x = 0
????