Re: jnu 2014 discussion

Posted by dhruv on May 12, 2015; 12:48pm
URL: http://discussion-forum.276.s1.nabble.com/jnu-2014-discussion-tp7596392p7596902.html

For, 52-54,

Solving the differential equation,

dx/[x(x-1)] = dt, gives us,

x = 1/[1-e^(t+c)]

where, c is constant of integration.

I think subsequent questions can be solved through this.