Re: DSE 2014 doubt

Posted by throwaway on Jun 25, 2015; 5:32am
URL: http://discussion-forum.276.s1.nabble.com/DSE-2014-doubt-tp7597718p7598420.html

@shar311 : Q3  - g(a) = f(a) - a.
Now it is given that the function's range is also [a,b]. This means that f(a) belongs to [a,b]. Thus it can be either equal to a, or bigger than a (but less than b). Which means f(a) >= a, and hence g(a) <= 0.

Similarly for g(b).