Re: ISI permutation and comb doubt

Posted by Tania123 on Apr 03, 2016; 6:33am
URL: http://discussion-forum.276.s1.nabble.com/ISI-permutation-and-comb-doubt-tp7584416p7599741.html

I solved it in the following manner.
Taking the pencils to be distinct, we can first choose 2 pencils out of 6 in 6C2 ways(each boy must have atleast one) These two pencils can be divided among the 2 boys in 2! ways. The remaining 4 pencils can be then divided among the 2 boys in 2^4 ways.
Therefore, total no. of ways= 6C2*2!*(2^4) =480
Where am I gong wrong?