Re: ISI 2010

Posted by samuraijack on Apr 10, 2016; 2:02pm
URL: http://discussion-forum.276.s1.nabble.com/ISI-2010-tp7588632p7599785.html

@Tania

I guess answer should be D
use nCr + nCr-1 = n+1Cr

(nC0 + n+1C1 ) + n+2C2......n+mCm

(n+1C0 + n+1C1) + n+2C2......+ n+mCm

(n+2C1) + n+2C2......+ n+mCm

(n+2C1 + n+2C2)+........n+mCm
(n+3C2) + n+3C3+.....n+mCm
Finally
n+mCm-1 + n+mCm = n+m+1Cm= n+m+1Cn+1 Option D