Re: JNU 2013

Posted by Dr. Strange on Apr 29, 2016; 3:10pm
URL: http://discussion-forum.276.s1.nabble.com/JNU-2013-tp7599821p7600218.html

Answer is d

eqn 1 : dP1/P1dt = u  this gives ln P1/PO= ut
eqn 2: dP2/P2dt = u+1  this gives ln P2/PO= ut +t

for t=1
ln P2 - ln P1 =1
P2/P1 = e