Demand of 1 for x= 5py/px+py
Demand of 1 for y= 5py/px+py
Demand of 2 for x= 10px/px+py
Demand of 2 for y= 10px/px+py
Total demand for x= (5py+10px)/px+py Total supply=10
Total demand for y= (5py+10px)/px+py Total supply=5
This gives px=0
Hence 10,5 is competitive as well as pareto efficient
and px=0 py=1 can be price vectors
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