Re: DSE 2015 answer

Posted by Abhitesh on Jan 09, 2017; 10:30am
URL: http://discussion-forum.276.s1.nabble.com/DSE-2015-answer-tp7600806p7603032.html

Your answer is correct.
Check each options
A. (n+1)p=n(1+p) => np+p=n+np => p=n ; not possible.
B. np=(n-1)(1+p) = n-1+np-p => p=n-1 ; not possible.
C. np cannot be a position integer if (n+1)p is a positive integer.