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Re: Doubts
Posted by
Abhitesh
on
Feb 06, 2017; 2:38pm
URL:
http://discussion-forum.276.s1.nabble.com/Doubts-tp7603095p7603162.html
g'(1)= g(1+h)-g(1)/h
Now f(1+h)=f(1) + f'(1)h = 1+h
=>f-1(1+h) = 1+h = g(1+h)
=>g'(1) = 1
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