Re: Doubt

Posted by AmyDunne on Jun 29, 2017; 3:48pm
URL: http://discussion-forum.276.s1.nabble.com/Doubt-tp7606622p7606626.html

X1 will use all K, so  l1 = (X1^2)/K

l2 = X2^2

L=l1 + l2 = (X2^2) + (X1^2)/K

So, L*K= K(X2^2) + (X1^2)