DSE 2011

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DSE 2011

Aranya
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Re: DSE 2011

Dreyfus
Q24. F(x) = F(x) - F(a)
Now F'(x) = d(F(x) -F(a))/dx =f(x)      ( F(a) is constant)
F''(x)= f'(x) and its given f'(x)>0 in [a, infinity)
F''(x) >0 hence convex
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Re: DSE 2011

Granpa Simpson
In reply to this post by Aranya
For 24 consider a point (x(0),y(0)) on the parabola...now when x=x(0), y=(1/4)*(x(0))^2...now the distance on (0,b) from this point is given by D^2=(x(0)-0)^2+[(1/4)*(x(0))^2-b]^2.
Now apply the condition for minima for the function at (0,0) you will obtain the condition, 2-b>0, or b<2.
 "I don't ride side-saddle. I'm as straight as a submarine"
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Re: DSE 2011

mrittik
Kulkal
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Re: DSE 2011

Aranya
In reply to this post by Aranya
Thanx a lot !
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Re: DSE 2011

Akshay Jain
Akshay Jain
Masters in Economics
Delhi School of Economics
2013-15
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Re: DSE 2011

Aranya
thanks @akshay
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Re: DSE 2011

Aranya
In reply to this post by Akshay Jain
this method is much easier!
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Re: DSE 2011

Aranya
In reply to this post by Aranya
Same paper qsn 40.help needed!
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Re: DSE 2011

kangkan
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Re: DSE 2011

Aranya
thank u @kangkan
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Re: DSE 2011

neha:)
In reply to this post by Akshay Jain
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Re: DSE 2011

Akshay Jain
@Neha...
It is given that the firm always employs input combination (x,ax) irrespective of the input prices...
this happens when the production function is of the form of perfect complements.
just chek for the options
1. at optimum x^a=y...this is not matching
2. at optimum ax=y....this is matching
3. at optimum x/a=y....not matching
4. at optimum x^(1/a)=y......not matching
Akshay Jain
Masters in Economics
Delhi School of Economics
2013-15
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Re: DSE 2011

neha:)
Thanku :)
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Re: DSE 2011

divyajain
can someone explain q52-54?
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Re: DSE 2011

Ridhika
In reply to this post by Akshay Jain
Akshay I dont quite follow your reasoning for this one.. What if an option had been b<1 .. then?