DSE 2014 doubt

classic Classic list List threaded Threaded
23 messages Options
12
Reply | Threaded
Open this post in threaded view
|

DSE 2014 doubt

cheesecake


How to go about this question?
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

cheesecake


this too!
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

onionknight
In reply to this post by cheesecake
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

onionknight
In reply to this post by cheesecake
Let price per unit be x
Maximise t-cx
subject to theta*sqrt(x)-t >=0

which boils down to maximizing theta*sqrt(x)-cx. Differentiate and set derivative=0, you'll get x=theta^2/4c^2

profit=theta^2/4c
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

cheesecake
In reply to this post by onionknight
ohh! got it! thanks.. i couldn't figure out how to remove the c :P
kk
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

kk
In reply to this post by onionknight
Question 42.   Ms. A selects a number X randomly from the uniform distribution
on [0; 1]. Then Mr. B repeatedly, and independently, draws numbers
Y1; Y2; :::: from the uniform distribution on [0; 1], until he gets a number
larger than X=2, then stops. The expected number of draws that Mr. B
makes equals
(a) 2 ln 2
(b) ln 2
(c) 2=e
(d) 6=e
kk
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

kk
am getting 1/2ln 2 not 2ln 2
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

cheesecake
How have you solved it?
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

shar311
In reply to this post by kk
can you please give the solution?
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

suchi
In reply to this post by kk
Hi!

has anyone solved this?

Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Amit Goyal
Administrator
This post was updated on .
Here is the complete solution:
Rob
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Rob
i dint understand the 4th step in this ques. plzz explain if anyone can do.thnks
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Amit Goyal
Administrator
Given the information, the first (N-1) of Y_1, Y_2, Y_3, ... , Y_N are less than x/2 and the Nth is greater than x/2. Therefore, Given the info, the conditional distribution of all random variables from Y_1 to Y_(N-1) is the same and equal to uniform U(0, x/2) and of Y_N is U(x/2, 1) and the forth line follows from this.
Rob
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Rob
Thanks a lot sir ,..sir one thing i want to noe from where i can practice these type of questions
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

shar311
In reply to this post by cheesecake
Hey guys, Please help me with this one..

Series 01, Q3 (Fixed point question). In the solution given by Amit Sir, function g(x) has been assumed as f(x)-x. Now later to prove that g(x) has a fixed point, it has been stated that g(a)>=0 and g(b)<=0 (x belongs to [a,b]). How do we come to this conclusion?

Series 01 Q6-10, I have a doubt, maybe a very trivial one which isn't clicking but would like members to help me clear it out. "Agent 1 strictly prefers bundle (a,b) to bundle (c,d) if, either a > c, or a = c and b > d." does this mean it is a case of perfect substitutes? Because while solving demand for 'x' by agent 1 is m1/px while that of 'y' is zero.

Any help would be much appreciated.
Thanks.
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Sris
This post was updated on .
it means the person lexographically prefers x to y....

between two bundles he will demand  the bundle that has more of x...and if two bundle has same amount of x ...he will prefer the bundle that has more y..

so dd for x= total income/price

and dd for y= zero..

google for further details
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

throwaway
In reply to this post by shar311
@shar311 : Q3  - g(a) = f(a) - a.
Now it is given that the function's range is also [a,b]. This means that f(a) belongs to [a,b]. Thus it can be either equal to a, or bigger than a (but less than b). Which means f(a) >= a, and hence g(a) <= 0.

Similarly for g(b).
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

shar311
Thanks a lot guys..:)
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

himanshu890
In reply to this post by onionknight
please elaborate it properly
i can not  figure out the the information given in the question
please help


DSE 2014
Q39
Reply | Threaded
Open this post in threaded view
|

Re: DSE 2014 doubt

Amit Goyal
Administrator
Detailed Solutions to DSE 2014 exams are posted here:
http://economicsentrance.weebly.com/lessons.html
12