ISI 2017 key

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Re: ISI 2017 key

Abhitesh
45 55 combination is pareto eff
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Re: ISI 2017 key

Akshay Pamnani
That is not the only Pareto Efficient outcome,how will you move them from (60,40) to (55,45).
Gaurav would not like that,would he?
So you would be making one person better off and the other one worse off necessarily,hence Pareto efficiency.
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Re: ISI 2017 key

Abhitesh
Same argument can be made about 90 10 also. In my opinion the prof has a social planner role he will like maximize combined utility.
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Re: ISI 2017 key

Akshay Pamnani
It can't be made for 90,10.Just draw the graph and see,both can be made better off there
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Re: ISI 2017 key

Abhitesh
Yeah it can't be done for 90 10. But what about the social planner role of researcher. There is no reason for him to prefer one guy over other.
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Re: ISI 2017 key

Akshay Pamnani
I don't think Pareto Efficiency cares about that,you are talking about equity really,equity is not present,but pareto efficiency is there.

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Re: ISI 2017 key

Akshay Pamnani
In reply to this post by Abhitesh
3-How did you get b
I got a.
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Re: ISI 2017 key

Abhitesh
Q1 - this is from welfare chapter of varian.
Q3 - In order to maximise social surplus use, P = MC = Q/2+31.
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Re: ISI 2017 key

Akshay Pamnani
1-Are you saying the same question is given in Varian,I could not find it
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Re: ISI 2017 key

Abhitesh
No... no that is the relevant chap.
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Re: ISI 2017 key

Akshay Pamnani
Yeah I know that.

And yeah I messed up the 3rd question,Crap!
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Re: ISI 2017 key

Akshay Pamnani
In reply to this post by Abhitesh
Check the 11th one,I got c
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Re: ISI 2017 key

Abhitesh
In reply to this post by Akshay Pamnani
how are you expecting in peb anyway.
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Re: ISI 2017 key

Abhitesh
In reply to this post by Akshay Pamnani
Q11 - Put G=tY+T0 i.e make budget balanced.
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Re: ISI 2017 key

Daffodils
Yes. 11 c
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Re: ISI 2017 key

Abhitesh
For a balance budget G=T=tY+T0
So Y=C+I+G
Y= c(Y-tY-T0)+I+ty+T0
Y= (c-ct+t)Y + I + (1-c)T0
Simplify this.
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Re: ISI 2017 key

Akshay Pamnani
In reply to this post by Abhitesh
22)Should be (c) right?
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Re: ISI 2017 key

Daffodils
22 c
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Re: ISI 2017 key

Abhitesh
In reply to this post by Akshay Pamnani
let a>1
aL+10 < aL+10a = a(L+10)
((aL+10).aK)^1/2 < a(L+10)^1/2.K^1/2 = aF . This is decreasing.

So 22 should be c

PS - And for Q1 Prop 1 seems to be efficient.
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Re: ISI 2017 key

Akshay Pamnani
Yeah,seems right!
I only checked for a>1.
Crap!
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