JNU 2011 Q.10

[Ankit Agrawal]

If f(x) = 1/(x^2) is integrated over the interval [1,2], then one gets

(a) 0
(b) log 2
(c) 1/2
(d) 1

My answer is working out to -1/2. Here's how i have done it:

Integral of f(x)= 1/x^2 is -1/x
Now inserting the interval [1,2] on this integral will give us:

= {-1/(1)} -{-1/(2)}
= -1 + 1/2
= -1/2

But the answer is (c) 1/2. Can you help me out?

[maahi]

u hv done a very silly mistake when we insert the values we insert value of b(2)first and value of a (1)later

[HRC ROCKZ]

Can somebody tell me.. from where to get the jnu answers?

[Ankit Agrawal]

Very silly, indeed!:D Got it. Thanks:)

On 30 Mar 2013 15:23, "maahi [via Discussion forum]" <[hidden email]> wrote:

u hv done a very silly mistake when we insert the values we insert value of b(2)first and value of a (1)later

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