JNU ECOM 2011 QUES 1-10

[Arushi :))]

QUES 1
Suppose two fair, six-sided dice are rolled. The probability of obtaining a value from the first dice that is at least two greater than the value from the second dice is:

Answer-c
QUES 2
If the radius of a circle is increased by 20%, then the area is increased by:

Answer-a
QUES 3
Let x, y and z be distinct integers. x and y are odd and positive , and z is even and positive. Which of the following statements cannot be true?

Answer-a
QUES 4
A line that is 13 units long has (4,1) as one of the endpoints. Which of the following could be the other endpoint?

Answer-a
QUES 5
If p & q are the roots of the equation x^2-bx+c=0, then what is the equation if the roots are
(pq+p+q) and (pq-p-q)?

Answer-a
QUES 6

Answer-b
QUES 7
Suppose we know that |a|< 3. Which of the following is enough to imply that |b|<5 ?

Answer-c
QUES 8
A population consists of the following seven numbers:
2003, 1999, 2001, 1997, 2000, 2005, 1995

Answer-b
QUES 9
Suppose a person's utility is given by u(x,y). If good x and good y are perfect substitutes, then the indifference curves are:

Answer-a
QUES 10

Answer-c

[SoniaKapoor]

Hey Arushi
The answer for quest 6 is a...
(x+7)>0
so x>-7

[econ14]

hey can u plz tell how to do question no. 7.
my answer is (a). plz help. thanx

[Arushi :))]

ooopssssss. i did that by mistake yeah a is right for sixth . Thanks Sonia.

For ques 7,
Hi Sandeep 'a' can't be the answer,
|a+b|<8
=> -8< (a+b) < 8
=> -8-a < b < 8-a
Now, its given that |a|<3, => -3< a <3
If i pick 2.5 as a,
then, i would get -10.5<b< 5.5
And we need |b|< 5, i.e -5<b<5
So we are getting a contradiction here.
I chose |a-b| <,= 2 because
-2 <,= (a-b) <,= 2
-2-a < -b < 2-a ( not strict inequality )
a+2 > b > a-2
a-2 < b <  a+2
Now, if I choose any -3 < a < 3
I will always get |b| < 5. ( you can check by taking numbers)

[econ14]

Thank you so much

[xyz]

can u plz tell how to do question no. 4?????
my answer is (c). kindly help

[Arushi :))]

The formula to find length of a line given its two end points is:
 underroot of this: (x1-y1)^2+(x2-y2)^2
Where (x1,x2) & (y1,y2) are the two endpoints of the line.
If you take c as the option , the two end points will be,
(4,1) & (3,7)
This will fetch you (1+36)^1/2 as the length . underroot 37. So, this can't be the right answer.
Taking (4,1) & (-1,13) gives (25+144)^1/2 = (169)^1/2 = 13
Which agrees with the given length of 13 units.
So (a) is the right option.