what was the correct option for variant or invariant?
On 18 May 2015 at 08:51, amalgamateking [via Discussion forum] <[hidden email]> wrote:
ok. I was confused between this option and not discont. The reason being at -1 and -3 the function isnt define (these points are not in domain). So there is no concept of checking for discontinuity/cont at points not even in the domain
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Obviously not. We can't say anything about the function beyond its domain. I must have not noticed the interval in which the function is defined. Highly likely.
i have one more confusion it was invariant of price or output?
On 18 May 2015 at 09:00, anadi [via Discussion forum] <[hidden email]> wrote:
Obviously not. We can't say anything about the function beyond its domain. I must have not noticed the interval in which the function is defined. Highly likely.
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one question was from simple keynesian model in which marginal propensity to save was decreasing and investment was increasing then what we can say about saving and output??
On 18 May 2015 at 09:04, amalgamateking [via Discussion forum] <[hidden email]> wrote:
Yea. The denominator was (x+1)(x+3). -1 and -3 are not in the domain then obviously (function not defined at those two pts)
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