Lots of DSE doubts - Please help!

[Homer Simpson]

Please explain the reasoning - thank you!

Additionally, the club-tribe question is from DSE 2011 - my confusion is about why (c) cant be a possible option?

How exactly does one approach 33??? Where can i look up on solving these kind of problems.

[ViV]

parabola passes through (0,0) point.. and take any arbitrary point (0,b) on the y axis(+ve axis). Since we want to minimize the distance.. This will be possible when we tk b<2 from d available options...

[econ14]

http://discussion-forum.2150183.n2.nabble.com/Club-Tribe-DSE-repeated-question-Basic-doubt-td7592649.html;cid=1402816856987-882#a7592661 FOR CLUB AND TRIBE  QUESTION

[econ14]

FOR 24 tsuki i think its given to us F(x) ie cdf which we obtain from integration of pdf........and the part at which pdf is increasing we draw a cdf  which is convex (see gujarati appendix )

[econ14]

for 25th it will be discont. bcoz between any two rational no.there are infinite irrational no.. for zero use limita to check....

[SoniaKapoor]

q 33 P(Z<0.5) = 1 -P(Z>0.5) = 1 -P(X>0.5,Y>0.5) = 1 -P(X>0.5)P(Y > 0.5) = 1 -0.25 = 0.75

[econ14]

hey plz explain q 39 2011 dse.........

[Dreyfus]

Q24. F(x) = F(x) - F(a)
Now F'(x) = d(F(x) -F(a))/dx =f(x)      ( F(a) is constant)
F''(x)= f'(x) and its given f'(x)>0 in [a, infinity)
F''(x) >0 hence convex

[econ14]

hey vaibhav plz help with q39 AND q 40 2011 dse...................

[Dreyfus]

Q39. We are given P(Reject H0 | True H0) = 0.09 ( its type 1 error)
P( reject H0 | true H0) = P( x<k) for 2x = k² = 0.09
→ k= 0.3 ( -0.3 is not possible as x E [0,1] )
ß = type II error = P( do not reject H0 l false H0) = P(x>0.3| 2-2x) = .49

[SoniaKapoor]

vaibhav,hw did you get F(x) = F(x) - F(a) ?

[Dreyfus]

Sonia....I used definition of integration....

[SoniaKapoor]

shouldnt it be F(x)-F(a)?

[Dreyfus]

Sry sandeep I mistakenly read as 2012...
Q39. 2011. IMG_20140616_001415.jpg

[Dreyfus]

Sonia....I hv written this only....

[SoniaKapoor]

oh my bad.I dont know what i was upto!