dse 2012

[Var1995]

someone help

[urvashi]

Hi take n to be 2 and then try to solve it you will get the ans

[Ansh malhotra]

[Var1995]

thanks

[dukhi jon snow]

for x [0,1].. sinx is always less than 1
so x^n* sinx is less than x^n
so integration of x^n* sinx is also less than x^n
so just integrate the x^n