f((f(f(x)) problem

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f((f(f(x)) problem

rongmon
if f(x) = 1/(1-x),  then f(f(f(x)) equals

a. 1/(1-x)

b. x

c. 1/x

d. 1-x



thanks
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Re: f((f(f(x)) problem

Noel
B
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Re: f((f(f(x)) problem

rongmon
thanks..wonder why i am ending up with option a.
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Re: f((f(f(x)) problem

Noel
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Re: f((f(f(x)) problem

Noel
In reply to this post by rongmon
This should help :)
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Re: f((f(f(x)) problem

rongmon
thanks-a-ton!

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Re: f((f(f(x)) problem

Ashima
In reply to this post by rongmon
Yes it's B
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Re: f((f(f(x)) problem

rongmon
f (x) = (1-x)/(1+x), x not equal to -1

f (f (1/x)) is

a. 1
b. x
c. x^2
d. 1/x


Thanks
       
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Re: f((f(f(x)) problem

Homer Simpson
getting (d)
“Operator! Give me the number for 911!”
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Re: f((f(f(x)) problem

rongmon
right you are.

can you share the workings?
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Re: f((f(f(x)) problem

Homer Simpson
here it is - f(f(1/x)) = f(1-(1/x)/1+(1/x)) - substitute (1/x)
                           = f(x-1/x+1)
                           = [1 - (x-1)/(x+1)]/[1+ (x-1)/(x+1)] - substitute (x-1)/(x+1)
                           = (x+1 - x+1)/(x+1 + x-1)
                           = 1/x
“Operator! Give me the number for 911!”
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Re: f((f(f(x)) problem

rongmon
thanks!
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Re: f((f(f(x)) problem

rongmon
In reply to this post by Homer Simpson
the second step,

you have (x-1) as numerator right, how is that reversed in the step below
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Re: f((f(f(x)) problem

rongmon
Figured, thanks.
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Re: f((f(f(x)) problem

Homer Simpson
ok :)
“Operator! Give me the number for 911!”