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hey can anyone solve dis out!!
You are an analyst for a metropolitan transportation authority. You are asked if it would improve efficiency to buy more buses, and if so, how many more should be bought. The operating cost of a bus is 30 during the day and 60 during the night, when higher wages must be paid to drivers and other workers. The daily capital cost of a bus, whether or not it is used, is 10. The demand for buses aggregated over persons and stops during the 12 hours of day and night, respectively d and n, are day: Qd = 160− Pd night: Qn = 80− Pn What prices should be charged to induce efficient ridership? a) Pd= 45, Pn= 55 b) Pd= 40, Pn= 60 c) Pd= 70, Pn= 80 d) Pd= 60, Qd= 40 |
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can any1 atleast try? plz?
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In reply to this post by sweta
tc = 30 Q + 10 for day
tc = 60 Q + 10 for night tc = 90 q + 20 mc = 90 equate mr=mc total q demanded=240 - p p = 240 - q mr = 240 - 2q 240 - 2q = 90 q = 150 q = 150 is the total supply of buses no other option adds up to 150 so its c |
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In reply to this post by sweta
I'm so sorry I appear to have found out the Q but the question asks for P.. I'm so sorry. Still thinking over the question.
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@aditi 5000 thanks!!
atleast u tried. although u got Q |
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In reply to this post by sweta
See the question asks for "efficient ridership" naa? So we should equate p=mc .. But even then, I am getting pn = 60 and pd = 30...
I also tried it out by equating mc and mr separately for day and night.. (though this does not have any theoretical backing) ...then i got pd = 95 and pm = 80.. either which way, i am not getting any of the options provided. |
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In reply to this post by sweta
Neither the P=MC nor the MC=MR approach seems to be working out here, so the only way we can do it is by looking at the options given to us.
Option A gives profit = 6100 Option B gives profit = 0 Option C gives profit = 2700 Option D gives profit =1200 So I'd say A. A very crude method though ![]() |
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hi chinni....
cn u pls post the link of this ppr....i m nt able to find it... |
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If anyone has solved this paper, could you please compare the answers with the ones I got:
SEC A 1(i) c (ii) b 2 a 3 a 4 a 5 a SEC B 1 c 2 d 3 d 4 a 1 d 2 c 3 b 4 Values missing 5 b 6 Values of a and b missing 7 a 8 b 9 c 10 b The link to the paper is here: GIPE_Modelquestions_ma.pdf |
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@chinni
how did u solve sec A q.5. the series question:5. What is the next number in the sequence 8 13 5 15 20 12 ? about sec C q4. shouldn't it be c) 0 and in q6. if we ignore values of a and b then the ans is d) & for q10. my ans is cumin c)24 just recheck if im correct but do tell q5. sec A |
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sec A q.5
8 13 5 15 20 12 I'm guessing the terms are like +5 and -8 so I just added 5 again. But it doesn't really make sense.. Can you come up with something? |
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may b u r right
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In reply to this post by Chinni18
I doubt it
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In reply to this post by sweta
And Q.4, you are right, it is (c)
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In reply to this post by Chinni18
For Q.10, I simply used 5!
Because that's the number of ways in which you can arrange them. And there isn't any form of repetition because each book is unique. How did you obtain 40? I'm sure I missed something. It can't be so straight-forward ![]() |
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its not 40 the ans is c) 24 see there are 2 economics books and 3 accounts books no of ways in which the 2 economics books (EE) can b arranged in themselves is 2! ie 2 ways & no of ways in which the 3 account books(AAA) can b arranged are 3! ie 6ways now the set of economics and accounts books can be arranged in 2 ways eg) EE AAA or AAA EE so total no of ways = 2 *2!*3! = 24 |
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In reply to this post by sweta
Yes that makes sense.. But the question does not mention that the economics and accounts have to necessarily be kept together, na?? But yes, I think you are right
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In reply to this post by sweta
hey chinni for q5 of secA
i thot the logic shud b diff btw (skipping the middle no. i.e 13) 8 n 5 is -3, diff btw 5 n 20 is +15 , so the diff btw 20 and next no shud be -3 so that gives 17. |
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hey cn u temme how did u get answer for the 2nd series in q7 sec C. ?
and q9 of the same sec... Also my answer for q8 is a) 4. |
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