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31.Ans 6.5%
Let c =C/L , y=Y/L
Given, n= (1/L)* dL/dt = 1.5%
Also given , elasticity=0.3 i.e dc/c = 0.3 dy/y .....(1) Since c=C/L
So, 1/c * dc/dt= 1/C * dC/dt - 1/L * dL/dt
Given,1/C * dC/dt <=3% and n=1.5%
So 1/c * dc/dt <=1.5%.......(2) Putting 2 in 1,
dc/c = 0.3 dy/y
So,1/c * dc/dt = 0.3 *(1/y)* dy/dt
from 2 we get,
1/y * dy/dt<=5% .......(3)
Now since y=Y/L
so 1/y * dy/dt= 1/Y * dY/dt - 1/L * dL/dt
From (3) we get,
1/Y * dY/dt <=6.5%
32.Yes answer should be 0
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