If x and y are real no. and it is known that x.y<2 ,then it must be the case
A. x and y are both less than 2.
B. x and y are both positive.
C. at least one of x and y is positive.
D. at least one of x and y is less than 2.
dreyfus is absolutely correct
you can eliminate options A,B and C very easily
it can't be option A or B because you can take x=3 (i.e. greater than 2) and y=(-1) (i.e. negative)
can't be option C because you can take x=y=(-1) to disprove it